Practice Problem #1
Solve for x: -3(2x + 1) = 2(x - 2)
OK, to start, we need to distribute the terms outside of parentheses to those inside the parentheses.
-3(2x + 1) = 2(x - 2)
_____ - _____ = 2x - 4
Now, let's isolate the x term on the left side of the equation.
-6x = 2x + _____
Move all x terms to the left side of the equation.
-3(2x + 1) = 2(x - 2)
-6x - 3 = 2x - 4
-6x = 2x - 1
_____ = - 1
Divide to find your answer.
x = ____
Practice Problem #2
Solve for x: -6x + 3 - 2x = 3 - 8x
Start by combining like terms on the left side of the equation.
-6x + 3 - 2x = 3 - 8x
_____ + 3 = 3 - 8x
That's odd. Once we combine like terms, you should see that right and left sides of the equation are identical. What is the solution to this equation?
OK, let's start by getting rid of the fraction on the left side.
4x - 2 = 50
Now, isolate the x term on the left side.
4x = ____
Practice Problem #3
Now, isolate the x term on the left side.
4x - 2 = 50
4x = 52
x = _____
Practice Problem #4
Solve for x: 
Now let's eliminate the fraction.
= 2x + 5
-x = 6x + 15
x = _____
Now, get all the x terms on the same side of the equation.
-x = 6x + 15
_____ = 15
Divide to find the final answer.
-7x = 15
x = 15/______
