Solving by Substitution
The second method for solving systems of equations is called substitution. This can be a good method when it is easy to isolate one of the variables in one of the equations. Here are the steps to solve a linear system by substitution:
- Solve one of the equations for one of the variables.
- Substitute that expression for the variable into the other equation.
- Solve for the variable.
- Substitute the value found for that variable into one of the equations and solve for the other variable.
Example 2
Solve the following system by substitution:
3x + 4y = 6
x + 2y = 4
Step 1: Solve one equation for either x or y. In this system, the second equation is the easiest to solve for x:
x + 2y = 4
x = - y
Answer: x = 4 - 2y
Step 2: Substitute the expression from step 1 into the first equation:
3(-2y + 4) + 4y = 6
Step 3: Solve for y:
y + + 4y = 6
Answer: -6y + 12 + 4y = 6
Step 4: Substitute solution for y into one of original equations and solve to find x. If y = 3,
x + y = 4
x + 2(3) = 4
x + 6 = 4
x =
Answer: x = -2
Now, check your answer, (3, -2) in both equations:
3x + 4y = 6
3(-2) + 4(3) = 6
-6 + 12 = 6
6 = 6
The ordered pair holds true for both equations, so (-2, -3) is the solution to the system of equations.
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