AP Chemistry - Semester 2: Equilibrium: the extent of Chemical Reactions
Sections: Introduction   |  Section 1   |  Section 2   |  Section 3   |  Section 4   |  Section 5   |   lab Lab

17.3 Expressing Equilibria with Pressure Terms

Often it is easier to measure the pressure of a gas than its concentration. We can plug in the ideal gas law to help relate the different variables to each other. Algebraically, we can see that the pressure is directly proportional to the molar concentration. Kp is the equilibrium constant obtained when the concentrations of all species are expressed as their partial pressures in atmospheres. Again, using the ideal gas law we can relate Kp to Kc. Kp = Kc(RT) deltangas.

Example: Calculate Kp for:

PCl3(g) + Cl2 arrow > PCl5(g) Kc = 1.67 at 500K

There is one mole of gaseous product and two moles of gaseous reactants so deltangas = 1-2=-1.

Kp= 1.67[(0.0821)(500)]-1 = 0.0407

17.4 Reaction Direction: Comparing Q and K

To determine if a reaction has reached equilibrium or to see in which direction the reaction is moving, we can compare Q with K.

  • If Q < K. If the value of Q is smaller than K, the reactants (denominator) are large relative to the products (numerator). equation The reaction will progress to the products until equilibrium is reached.
  • If Q > K. If Q is larger than K then the products (numerator) will decrease and the reactants (denominator) increase until equilibrium is reached.
  • If Q = K. This situation exists only if the concentrations of both sides have attained equilibrium.

Example: using the reaction:

N2(g) +O2(g) arrow >2NO(g) Kc = 0.10 at 2000oC

If we add 1 mole nitrogen and 1 mole of oxygen to a 1 L container.

equation

Initial concentration of N2 = 1mol/L
Initial concentration of O2 = 1mol/L
Initial concentration of NO = 0

Qc=0

The reaction will proceed to the right.
using the same reaction:

N2(g) +O2(g) arrow >2NO(g)

If we add 1 mole nitrogen,1 mole of oxygen and 1 mole NO to a 10L container

equation

Initial concentration of N2 = 1mol/L
Initial concentration of O2 = 1mol/L
Initial concentration of NO = 0.1mol/L

equation

Qc>Kc so the reverse reaction will take place

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